normal to the discontinuity. Similarly, the components of the bulk velocity upstream of the shock are chosen as and , where α the angle between the bulk velocity and the normal component of the velocity. Furthermore, a parameter λ is used to denote the pressure anisotropy
and another parameter x is used to denote the ratio of density
[7] | I still don't fully get it... |
For a perpendicular shock, , we have the conservation relations reduce to
The quantities downstream of the discontinuity are
Substituting these into the energy equation leads to
where .
Now we can do some simple estimations. Assume we have isotropic upstream solar wind with , , in GSM coordinates, and . We want to estimate the downstream anisotropy given a density/tangential magnetic field jump of 3.
using Vlasiator: kB, μ₀, mᵢ
n1 = 2e6 # [m^3]
v1 = 6e5 # [m/s]
B1 = 5e-9 # [T]
T1 = 5e5 # [K]
λ1 = 1.0
As = kB * T1 / (mᵢ * v1^2) # 0.011
Am = B1^2 / (μ₀ * mᵢ * n1 * v1^2) # 0.016
x = 3 # downstream/upstream jump density ratio
y = 1 / x
λ2 = (-2λ1*y^3 + λ1*(2As+Am+2)*y^2 - Am*λ1) /
(6λ1*y^3 - 4λ1*(2As+Am+2)*y^2 + (2λ1*(4As+1+2Am)+2As)*y)
@show λ2
which shows .
In Vlasiator 2D southward IMF equatorial run I get 15 in a large area with spatial resolution 300 km downstream near the shock, which is much larger than this. I later realized that this indicates that the run is problematic, because the periodic condition in the out-of-plane z direction, which is also the parallel direction, prohibits any parallel heating. This in turn causes unphysical anisotropy values in the downstream region.
In Vlasiator 2D southward IMF meridional run I get over 10 in a narraw region downstream of the shock, but for most part of the magnetosheath, the value is between 1 to 5, except the region near the magnetopause where again we have values over 10.
Another thing to note is that, if you set the jump ratio to 4 in the above calculations, the downstream anisotropy will become 0.6. This indicates that under this set of upstream conditions, the jump ratio shall never be close to 4 if you want anisotropy value > 1!
Parallel shocks are more special in that the magnetic field strength remains unchanged so the equations effectively describe pure gasdynamic solutions. Kuznetsov & A.I.Osin, 2018 presents a simplified solution in a 1D parallel shock case with parallel and perpendicular thermal energy heat fluxes and included. Note again the original CGL theory assumes 0 heat fluxes.
In the observation comparison paper Slavin and Holzer, 1981 for quasi-perpendicular shocks, they concluded that the variations in shock stand-off distance and shape are ordered by the sonic Mach number and not other Mach numbers involve magnetic field. In other words, they think the bow shock is a gasdynamic structure.
However, even in neutral fluid theory, the determination of shock location as well as shape is still a research problem. Imagine the simplest scenario where there is a static ball in the air with infinite mass. Assuming purely homogenous air with known density, velocity and pressure in the upstream, can you tell me the exact location of shock stand-off distance with pen and paper?
On top of that, the introduction of EM field complicates the story. Especially in the case of a parallel shock, the plasmas get "shocked" both upstream and downstream, and the stand-off distance of the shock may not be a single point theoretically. In some sense, normal magnetic field to the boundary "thickens" the shock front.
Observationally, Pioneer 6 showed that the ion temperature anisotropy in the solar wind at 1AU generally has [8]. It may possibly be explained by the conservation of the 1st adiabatic invariant Scarf+, 1967[9].
[8] | There are 3 interesting discoveries from Pioneer 6 ARC plasma measurements: |
anisotropic ion thermal distribution ();
presence of a 3rd species, helium, from charge-to-mass ratio analysis of the angular and energy distributions.
[9] | I love this old paper. The pioneers in our field did real physics. |
is conserved as the collisionless solar wind flows outward from the sun. Near the solar equator the mean field magnitude declines with
and
from the Parker spiral solar wind model and rad/s being the angular frequency of the rotation of the sun.
The adiabatic equation in the perpendicular direction indicates that the perpendicular thermal energy declines with B. Assuming in the rest frame the distribution function is a bi-Maxwellian of the form
the conservation of the total thermal energy
yields
These allows us to evaluate the variations in and originating from isotropic distribution on the surface of the sun. Starting from , the predicted anisotropy at Earth can go beyond 20! Therefore in fact, the reasonable question to ask is why the actual solar wind anisotropy factor is so small.[10]
[10] | This is new to me. Since I've been involved in the simulation reseach, we always apply isotropic distribution in the upstream solar wind condition, which I guess is primarily due to the fact that we are mostly using MHD. Should we now use more realistic distributions with the kinetic models? |
On the other hand, the opposite case, , is also observed and believed to be related to local ion heating by macroscale compressions (e.g. high/low speed streams interaction) or plasma instabilities Barne+ 1975.
Here I list the mirror instability criterion as an additional relation to determine the pressure anisotropy downstream of the shock from the book Plasma instabilities and nonlinear effects by Hasegawa 1975,
Using data from the AMPTE/IRM spacecraft, Hill+ 1995 have shown that the double adiabatic equations do not hold in the magnetosheath. Moreover, the thermal behaviour of the magnetosheath is studied by Phan+ 1996 using WIND spacecraft data. They report that most parts of the magnetosheath are marginally mirror unstable.[11]
[11] | WIND has electron observations and shows in the magnetosheath. |